www.1862.net > 在图中,AC⊥BC,∠AFC=∠AED=90°,AD平分∠BAC,则有...

在图中,AC⊥BC,∠AFC=∠AED=90°,AD平分∠BAC,则有...

解:∵ABCDE为正五边形 ∴∠AED=(5-3)*180/5=108° 又∵AE=ED ∴∠EAD=∠EDA=(180-∠AED)/2=(180-108)/2=36° 同理可知∠AEB=∠ABE=36° so∠AFE=180-∠EAD-∠AEB=180-36-36=108°

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