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2/51×35分之4×7/4等于多少用分数表示

2/51×4/35×7/4 =2/51x1/5 =2/255

5/17-51/4+2/3等于多少分之几 5/17-51/4+2/3 =60/204-2601/204+136/204 =-2405/204

2/51×34/35×7/6 =4/105x7/6 =2/45

51又3分之2×5分之2-7分之4 =(51+2/3)x2/5-4/7 =(50+1+2/3)x2/5-4/7 =20+2/5+4/15-4/7 =20+6/15+4/15-4/7 =20+2/3-4/7 =20+14/21-12/21 =20+2/21 =420/21+2/21 =422/21

51分之2×35分之34×4分之7 =(51×5)分之17 =255分之17 本题是先约分,而后再计算,这样比较简便

1/1 ==> 分子+分母=2, 共1个数 1/2,2/1 ==> 分子+分母=3,共2个数 1/3,2/2,3/1 ==> 分子+分母=4,共3个数 1/4,2/3,3/2,4/1 ==> 分子+分母=5,共4个数 1/5,2/4,3/3,4/2,5/1 ==> 分子+分母=6,共5个数 规律已经可以看出来了 因此,第51...

51又2/3×3/5+71又3/4×4/7+91又4/5×5/9 =(50+5/3)×3/5+(70+7/4)×4/7+(90+9/5)×5/9 =30+1+40+1+50+1 =123

解答 =155/3×3/5-7/4 =31-7/4 =29又1/4

51又2/3×3/5+71又3/4×4/7+91又4/5×5/9 =(50+5/3)×3/5+(70+7/4)×4/7+(90+9/5)×5/9 =30+1+40+1+50+1 =123

解: 1/(2×3×4) +1/(3×4×5)+...+1/(49×50×51) =½×[1/(2×3) -1/(3×4)+1/(3×4)-1/(4×5)+...+1/(49×50)- 1/(50×51)] =½×[1/(2×3) -1/(50×51)] =1/12 -1/5100 =212/2550

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